Can 2 = 1??

Question

If a=1 and b=1 then a = b
Multiply by a* then a* = ab
Subtract b* then a* - b* = ab - b*
Factor then (a + b)(a - b) = b(a - b)
Divide by (a - b) then (a + b) = b
Then 1 + 1 = 1
Then 2 = 1
10 points to the first that can show me I'm wrong

Answer 1

(a-b) = 0

In this problem, division by zero is not allowed, and thus your math is incorrect.

Answer 2

Here is the solution

Line1--> If a=1 and b=1 then a = b
Line2--> Multiply by a* then a* = a*b
Line3--> Subtract b* then a* - b* = ab - b*
Line4--> Now since a=b so a*=b*
Putting these values in Line 3 we get
Line5-->a*-a*=aa-a*
Now when a=1 and b=1, line 5 becomes
Line6--> 0=0 hence proved that you are wrong !!


:) :)

Answer 3

weird! its quite simple. a-b is 1-1 and 1-1 is 0. You CANNOT divide by zero!

Answer 4

if a=b
the a-b=0
to follow your math,
a* - b* = ab - b*
factor: (a+b)(a-b) = b(a-b)
compared to a-b = 0, then
(a+b)(0) = b(0)
0 = 0
besides, in math, different letters mean different value, so the "if a=1 and b=1" part is not mathematically valid.

Answer 5

it is simple.

(a + b)(a -b) = b(a - b)
which is mean:
(a + b)( 0 ) = b( 0 )

you should remember two laws:

1. 0 * (anything) = 0

2. (anything) ^ 0 = 1





( maybe you ask me:
what about this one:

0 ^ 0 = ?

or:

(infinity) * 0 = ?

who knows? maybe you find out some day.)

Answer 6

you would have a zero in your solution and you cannot divide by a 0 so you are wrong

Answer 7

(a + b)(a - b) = b(a - b)

Now if a=b=1, then

(a+b)*0 = b*0

Anything * 0 = anything else * 0. It all falls apart.

Answer 8

2 is the loneliest number since the number one

Answer 9

multiply by a:
a^2=ab

u got mistake here

Answer 10

Yeah, its called marriage.