differentiate e^-x(2-2x);?

Question

double checking. i am a math fiend. I best get it right.

i wrote it wrong, thus I feel the problem is being misunderstood:
it is the (2-2x) times e^-x. aka f'g+gf'

Answer 1

the answer should be

(4x-2)e^((2x^2) - 2x)

Answer 2

Differentiate
e^{-x(2 - 2x)} = e^(-2x + 2x²)

d{e^(-2x + 2x²)}/dx = (-2 + 4x)e^(-2x + 2x²)
= -2(1 - 2x)e^{-2x(1 - x)}
= 2(2x - 1)e^{2x(x - 1)}

Answer 3

(-2+4x)e^-x(2-2x)

Answer 4

d/dx((e^-x)(2-2x)) =-2e^-x - (2-2x)e^-x = -(e^-x)(4-2x)

Answer 5

-(e^-x)(2-2x)-2(e^-x)

-4e^(-x)+2xe^(-x)
(-4+2x)(e^-x)