a ship leaves port and travels 120 miles at the bearing of S 29 degreees west. how far south and how fat west is the ship?
evaluate tan (tan^-1(7/11)
evaluate sin(sin^-1(3/2)
2007-01-07 17:50:29 · 3 answers · asked by dojorno5 2 in Science & Mathematics ➔ Mathematics
first queation bout the ship too plz
2007-01-07 17:56:51 · update #1
first = 7/11
second = 3/2
its just taking a function of its inverse, making it the number in the parenthesis
2007-01-07 17:53:18 · answer #1 · answered by mike b 1 · 0⤊ 0⤋
the ship question: Think triangles, your ships path is the hypotenuse and it's direction of travel (S 29 W) forms one of the angles... So you use the Pythagorian theorem and what you know about sin (sin of an angle = opposite over hypotenuse) to find the two legs of the triangle.
Hint: the longer leg is the distance south, the shorter is the distance west. (a^2 + b^2 = c^2) Good luck!
2007-01-08 02:21:03 · answer #2 · answered by lynn y 3 · 0⤊ 0⤋
cos = adjacent / hypotenuse, so adjacent = hyp * cos
120 * cos(29) = 104.9 miles South
Similarly,
120 * sin (29) = 58.2 miles West
The tangent of an inverse tangent gets you back where you started, at 7/11
WARNING- Trick question! The sine of an angle can only range from -1 to +1
3/2= 1.5 so the inverse sine does not exist! And if THAT doesn't exist, how can you take the sine of it?
2007-01-08 02:02:57 · answer #3 · answered by Alan 6 · 0⤊ 0⤋