MATH help pls???

Question

pls help me? i go to this private christian school but they dont have a really good math teacher ( believe me he even admits it) and we appreciate him teaching but sometimes it just doesnt help much. and he is an english major... so he doesnt really know a lot of math : /.


so i really REALLY do need help.

and it would be nice if u can explian how u got to the answer. thanks ;)


here it is.

x4* - y3* divided by x-y **** those are supposed to be exponents

ok i figured out how to write exponents....

so my equation is.

x^3 - y^3 / x-y
and it really is x^3 not x^4. thanks

Answer 1

Let's rewrite the equation so everyone can understand it.
^ = denotes exponent

So, your equation ----> x4* - y3* divided by x-y
Becomes ----> (x^4 - y^3) / (x - y)

I've posted an image of the equation at
http://tinypic.com/view/?pic=313rno4

Is this the way your problem reads?
If so, you have to do long division.

==============

EDIT:
Cheezz has e-mailed me and said the equation is:

x^3 - y^3
----------
x - y

The numerator is a difference of cubes, which factors to:
(x^3 - y^3) -------> (x - y) (x^2 + xy + y^2)

Now, you have:
(x - y) (x^2 + xy + y^2)
----------
(x - y)

The (x - y) over (x - y) cancels, leaving:
(x^2 + xy + y^2)

More information about factoring cubes can be found at:
http://www.purplemath.com/modules/specfact2.htm

These are some good math sites too!
http://www.purplemath.com/
http://www.webmath.com/
http://algebrahelp.com/
http://www.quickmath.com/
http://www.homeworkhelp.com/

Good luck in your classes.

~ Mitch ~

===================

Golly gee whiz there "Answer Man"....
Nice of you to show up an hour later once Cheezz and I have hammered out the problem.

Too bad you showed up a little too late.

Answer 2

x^3 - y^3 / x-y
not so hard...
so you should think x values and y values separately.
think of it as a fraction
(x^3 over x ) - (y^3 over y)
Cross one x denominator and one x numerator from the first one to make it x^2. Cross one y denominator and one y numerator from the second one to make it y^2.
Now, it became x^2 - y^2. That is the simplist you can make it.
If you need more explanations on this, email me at [e-mail]

* You should keep in mind that this is not a polynomial...you know... the (x-2)(x+2) stuff...

Answer 3

I'm glad you changed the 4 to a 3 because now it has a solution.

This is a factoring and simplification problem.

First you have to factor the top term (x^3 - y^3)
that factors into (x-y)(x^2+xy+y^2)

Then you can put that term into the whole expression as follows
(x-y)(x^2+xy+y^2) / (x-y)

You have a term (x-y) on top and on bottom of the division expression, so they cancel and you have left (x^2+xy+y^2).

Thats the lowest simplification.

Answer 4

The roots (or as a substitute the identical numbers with reverse signal) have got to upload to the center coefficient of the quadratic. The center coefficient is seven, 2 numbers that upload to seven and range through one are three and four. Since three+four = 7 and four - three =a million q might be the ones identical numbers accelerated in combination. three*four=12 So q = 12.