Please Help me with this Algebra 2 Problem. Thank you so much?

Question

Simplify this expression completely.

3/(x^2 + 5x +6) - 2/(x^2-4)

thnx

Answer 1

3/[(x + 2)(x + 3)] - 2/[(x + 2)(x - 2)]

Let's multiply the numerator and denominator of the first fraction by (x - 2)

3(x - 2)/[(x + 2)(x + 3)(x - 2)] - 2/[(x + 2)(x - 2)]

Let's multiply the numerator and denominator of the second fraction by (x + 3)

3(x - 2)/[(x + 2)(x + 3)(x - 2)] - 2(x + 3)/[(x + 2)(x - 2)(x + 3)]

Now the denominators of the two fractions are the same, and we can just subtract the numerators:

(x - 12)/[(x + 2)(x + 3)(x - 2)] <- James Chan agrees

kpxxbladexx415 gets (x - 9) for the numerator because kpxxbladexx415 thinks that -2 times 3 is -3. It isn't. It's -6.

Surely Nicholas is joking, with his whimsical treatment of subtracting fractions.

Answer 2

First, you work on the numerators 3-2 =1
Then you work on the denominators:
a. the X squares council each other out
b. subtract - 4 from +6 = +2

and the simplified expression turns out to be 1/(5X+2)

Answer 3

=3/(x+2)(x+3) - 2/(x+4)(x-4)
taking resiprocal
(x+2)(x+3)/3 - (x+2)(x-2)/2{taking LCM}
=2(x+2)(x+3)- 3(x+2)(x-2)
=2(x^2+5x+6) - 3(X^2 -4)
= 2x^2 +10x +12 - 3X^2 +12
= - x^2 +10x +24
= - {x^2 -10x -24}
= - [x^2 - 12x + 2x -24]
= - { x(x-12)+2(x-12)]
= - [ (x-12) + (x+2)]
= (x-12) +(2 -x)
= 1/x-12 + 1/2-x
factorize 2 get the answer

Answer 4

I'm so dumb, so here is my dumb answer:

1/x^2+(3/5x)-1

Definitely wrong, but I tried, sorry I haven't had to do any math for a month and half, which is long enough for me to forget stuff like that.

Actually: The guy ahead of me is right, you'd probably factor that sort of thing...HAHAHA. Dang, Calculus is gonna stink next semester!!!!

Answer 5

3/(x^2 + 5x +6) - 2/(x^2-4)
= 3/[(x + 2)(x+3)] - 2/[(x -2)(x+2)]
= [ 3(x - 2) - 2(x+3) ] / [(x+2)(x+3)(x-2)]
= (x - 12)/ [(x+2)(x+3)(x-2)]
= (x-12) / (x^3 + 3x^2 - 4x - 12)

Answer 6

3/(x+3)(x+2) - 2/(x-2)(x+2)

3(x-2)/(x+3)(x+2)(x-2) - 2(x+3)/(x-2)(x+2)(x+3)

3x-6 -2x - 3 /(x+3)(x+2)(x-2)

x-9/(x+3)(x+2)(x-2)
Simplify and thats your answer.

Answer 7

i love the way you requested. right here's the hint to sparkling up the priority... an X intercept of the graph is the position the position the graph cuts the X-axis. the fee of 'y' on the X-axis is 0. consequently, to locate the X-intercepts, make y=0 and sparkling up the equation. The roots of that equation are your x intercepts. further, for Y-Intercepts, make x=0 contained in the equation; you receives the Y-intercept.

Answer 8

i think you should divide through by the numerator then the answer is ,oops i got to ask my math teacher.sorry i forgot.

Answer 9

so hard!