a)1/1000
B)1/10
C)-1000
D)1/729
2007-01-07 16:57:44 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(6^0+3^2)^-3 = ( 1 + 9 ) ^-3 = 10^-3 = 1/ 1000
so a is the correct answer
2007-01-07 17:00:44 · answer #1 · answered by James Chan 4 · 0⤊ 0⤋
A) 1/1000
Here's the work.
(6^0+3^2)^-3 =
[(6 raised to the power of zero) PLUS (3 raised to the power of 2)] ALL RAISED to the power of negative-3 =
[(1) + (3 x 3)] ALL RAISED to the power of negative-3 =
(1+9) ALL RAISED to the power of negative-3 =
10 RAISED to the power of negative-3 =
1/(10 RAISED to the power of positive-3) =
1/(10 x 10 x 10) =
1/1000
I hope this is of some help to you.
2007-01-08 01:05:27 · answer #2 · answered by G. Rex 3 · 0⤊ 0⤋
(6^0+3^2)^-3 = 1/(1 + 9)³ = 1/1000
The answer is a.
2007-01-08 01:02:12 · answer #3 · answered by Northstar 7 · 0⤊ 0⤋
(6^0+3^2)^-3
=(1+9)^-3
=10^-3
=1/10^3
=1/1000
Theredoew (a) is correct
2007-01-08 01:08:30 · answer #4 · answered by alpha 7 · 0⤊ 0⤋
6 to the power of 0 is 6
3 to the power of 2 is 9
6+9=15
15 to the negative power of 3 is?...I think its a fraction, but don't remember.
2007-01-08 01:07:45 · answer #5 · answered by Getsbetterwithtime 3 · 0⤊ 2⤋
a
2007-01-08 01:38:53 · answer #6 · answered by gangreless 2 · 0⤊ 0⤋
wow... i thought it was 6
2007-01-08 01:04:54 · answer #7 · answered by tanj 4 · 0⤊ 2⤋