Please solve the open sentence
(4x-2)/5 + 14-3x/4 > or = 3
2007-01-07 16:43:26 · 5 answers · asked by brett y 1 in Science & Mathematics ➔ Mathematics
x=-2
Get common denominator (20 in this case), multiply top by the number need to get cancel out the 20 so
4(4x-2) + 5(14-3x)=60 then
16x-8 + 70-15x=60 combine like terms
x + 62=60 get x by itself
x=-2
plug answer into original problem to check it
2007-01-07 16:54:38 · answer #1 · answered by vavavoom14 2 · 0⤊ 0⤋
(4x - 2)/5 + 14 - 3x/4 ⥠3
Clear the denominators by multiplying thru by 20
4(4x - 2) + 14*20 - 5*3x ⥠3*20
16x - 8 + 280 - 15x ⥠60
x ⥠60 + 8 - 280
x ⥠-212
2007-01-08 00:55:08 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋
(4x - 2)/5 + 14 - 3x/4 >= 3
Let's get rid of all the fractions by multiplying both sides by 20.
4(4x - 2) + 14(20) - 3x(5) >= 60
16x - 8 + 280 - 15x >= 60
Now, let's move all terms with no x on the right hand side.
16x - 15x >= 60 + 8 - 280
x >= -212
2007-01-08 00:47:45 · answer #3 · answered by Puggy 7 · 0⤊ 0⤋
(4x - 2)/5 + 14 - 3x/4 ⥠3
Multiplying through by the LCD,
16x - 8 + 280 - 15x ⥠60
x ⥠- 212
2007-01-08 01:01:46 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
16x-8+280-15x>or=60
x>or=-212
2007-01-08 05:04:32 · answer #5 · answered by ♫tweet75♫ 3 · 0⤊ 0⤋