Original equation
a = (1/2)bc^2
Your goal is to get b by itself, so you want to cancel anything on the same side as b...
Start by multiplying by 2 on both sides; this will cancel the 1/2:
2a = bc^2
Now divide by c^2 on both sides; this will cancel the the c^2 on the right:
2a / c^2 = b
Reverse the equation so b is on the left:
b = 2a / c^2
There's your equation solved for b.
2007-01-07 16:25:13
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answer #1
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answered by Puzzling 7
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B=2a/c^2
2007-01-08 00:30:43
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answer #2
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answered by B T 3
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a=(1/2)bc^2 [Multiply both sides by 2}
2a = bc^2 [Divide both sides by c^2
2a/c^2 =b <---- and here's your answer.
2007-01-08 00:27:36
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answer #3
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answered by ironduke8159 7
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a = (1/2) b(c^2)
Your first step is to get rid of that pesky fraction. Multiply both sides by 2, and that'll do it.
2a = b(c^2)
Now, you want to get b all by itself. To do that, you must *divide* both sides by c^2.
2a/(c^2) = b
2007-01-08 00:25:42
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answer #4
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answered by Puggy 7
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divide both sides by .5 and c^2 to get
b=2a/c^2
2007-01-08 00:24:53
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answer #5
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answered by Anonymous
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a=(1/2)bc^2
It's the same as...
a=(bc^2)/2
then solve...
2a=bc^2
2a/(c^2)=b
2007-01-08 00:28:57
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answer #6
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answered by Sarah 2
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(2a)/c^2 = b
Edit: c not equal to 0.
2007-01-08 00:25:04
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answer #7
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answered by S. B. 6
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