Adult tickets for a play cost $11 and child tickets cost $10. If there were 23 people at a performance and the theater collected $246 from the ticket sales, how many children attended the play?
I have almost got it I think but I just cannot get there.
Is it 11x+10y=246
I know this is the equation but I get lost from there
Thank you in advance for the help!!
2007-01-07 16:04:47 · 4 answers · asked by richardsonlover12 1 in Science & Mathematics ➔ Mathematics
yOU HAVE ONE OF THE EQUATIONS. yOU ARE CORRECT 11X + 10Y = 246 IS ONE OF THE EQUATIONS WHERE X = ADULT TICKETS AND Y = CHILDS TICKET. hOWEVER YOU ALSO NEED AN EQUATION RELEATING HOW MANY ADULT TICKETS AND CHILD TICKETS WERE BOUGHT.
THERE WERE X AMOUNT OF ADULT TICKETS BOUGHT AND Y AMOUNT OF CHILD TICKETS BOUGHT FOR A TOTAL OF 23. THE EQUATION WHICH REPRESENTS THIS IS:
X + Y = 23
nOW YOU HAVE TWO EQUATIONS:
11x+10y=246
x + y = 23
yOU CAN SOLVE BY SUBSTITUTION
GET X BY ISELF IN EQUATION 2
X + Y = 23 BECOMES X = 23 - Y
gO BACK AND SUBSTITUTE 23 - Y IN FOR X IN FIRST EQUATION:
11(23 - Y) + 10Y = 246
dISTRIBUTE THE 11 OVER 23 - Y AND YOU GOT:
253 - 11Y + 10Y = 246
cOMBINE -11Y + 10Y AND YOU GET -Y
253 -Y = 246
SUBTRACT 253 ON BOTH SIDES AND YOU GET:
-Y = -7
dIVE BY -1 ON BOTH SIDES AND YOU GET
Y = 7
SINCE Y EQUALS CHILD TICKETS 7 CHILDREN HAD A TICKET..
NOW SOLVE FOR ADULT TICKETS
YOU KNOW X + Y = 23
AND Y = 7
REPLACE Y WITH 7 AND YOU GET:
X + 7 = 23
SUNTRACT 7 FROM BOTH SIDES AND YOU GET
X = 16
SINCE Y = 7 AND X = 16
16 ADULTS AND 7 CHILDREN WENT TO THE SHOW.
2007-01-07 16:15:48 · answer #1 · answered by googooslide2000 3 · 0⤊ 0⤋
Good start.
Now remember x+y = 23
so substitute
x = 23-y
so 11 (23-y) + 10 y = 246
253 -11y + 10y = 246
7 = y
so x = 16 Therefore 16 adults and 7 kids
2007-01-08 00:09:05 · answer #2 · answered by ignoramus 7 · 1⤊ 0⤋
you have one equation in two unknowns ...
you need a second eqn
have you tried
x + y = 23
as the second one? (it's the eqn descirbing the number of total tickets)
NOTE: x = 23 -y might serve as the "plug-in" substitution
I'd do the rest of the symbolic manipulation, but it's probly best if you do a portion of the werk as well...
good luck
2007-01-08 00:05:57 · answer #3 · answered by atheistforthebirthofjesus 6 · 1⤊ 0⤋
Sorry brother! Failed algebra 2!
2007-01-08 00:06:59 · answer #4 · answered by fuji 1 · 0⤊ 1⤋