you reach into the jar and without looking, remove 2 jelly beans. what is the probablity that you will remove 2 pink jelly beans?
2007-01-07 15:58:49 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
If you don't think for yourself and do your own homework, school will have been pointless cause you will have gained nothing.
2007-01-07 16:02:33 · answer #1 · answered by T.M.Y. 4 · 0⤊ 0⤋
There are 15 jellybeans
At first there is a one in three chance of choosing a pink one.
Once it is removed, there are 14 jelly beans. 4 are pink, so there is a 2 in 7 chance of choosing another pink one.
So, the answer is 1/3 x 2/7 = 2 in 21 chance.
Note that if you threw the pink jelly bean back in, then it would be a 1/3 x 1/3 chance which is 1 in 9.
2007-01-07 16:03:59 · answer #2 · answered by ignoramus 7 · 0⤊ 0⤋
P(pink) = (5/15)(4/14) = 20/210 = 0.095238
2007-01-07 16:14:31 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
11.1 percent chance of picking out 2 pink jellybeans. Its the product rule because it is the chance of 2 mutually exclusive events taking place.
5/15 chance x 5/15 chance = 1/3 x 1/3 = .1111 = 11.1%
2007-01-07 16:02:49 · answer #4 · answered by Scoonba 2 · 0⤊ 1⤋
15 jellybeans makes a total of 210 possibilites
50 of those possibilities are one pink one blue (order drawn)
50 of those possibilities are one blue one pink (order drawn)
90 of those possibilities are two blue
20 of those possibilities are two pink
that makes an estimated possibility of 2:21
2007-01-07 16:09:38 · answer #5 · answered by Edanhsil 1 · 0⤊ 0⤋