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okay heres 4 problems that i simply cannot doooo! helllp please!

1. 4th root of [(5x+2y) to the negative 12th power]... x and y are variables

2. 5th power of [4x(y to the 5th power)]
over the 5th power of [125(x the the 4th power)]

3. 5 over the 3rd power of 9

4. the [3rd power of 2 ]over the [3rd power of4(x) to the power of 2]


the last 3 are fractions...hence the word "over"

2007-01-07 12:44:36 · 3 answers · asked by Anonymous in Education & Reference Homework Help

3 answers

If you go to this website it will break all of the algebra down for you.
www.purplemath.com

2007-01-07 13:01:17 · answer #1 · answered by Amazing_clarity 4 · 0 0

1. you can rewrite the first one so that it is (5x+2y)^(-12/4), that simplifies to (5x+2y)^(-3) or 1/[(5x+2y)^3]. You can expand but i doubt you need to.

2. you can write it so that the whole fraction is to the 5th power and then just simplify what is in the fraction first. inside you cross out the common factors and get. (4y^5)/(125x^3). It is then that whole fraction to the 5th, but it's a bit ugly to expand, i don't know if you typed it wrong, but the number becomes too big.

3. this is just 5/(9^3) = 5/729

4. First it is (3^2)/[(4x)^3]^2 = 9/[(64x^3)^2] = 9/(4096x^6) and that is your answer

2007-01-07 13:06:44 · answer #2 · answered by shmousy636 3 · 0 0

a million) sq. the two facets: x=sixteen 2) upload 7 to the two facets then sq. the two facets so sqrtx=7 and x=40 9 3) subtract 9 the two facets then sq. the two facets so sqrtx=-9 and x=80 one yet 80 one does not examine in unique equation so answer is "no answer" 4) subtract 2 the two facets, then divide by potential of four then sq. the two facets so 4sqrt.z=-2 or sqrt.z=-a million/2 or z=a million/4 yet a million/4 does not examine in unique equation so "no answer"

2016-11-27 02:56:02 · answer #3 · answered by ? 4 · 0 0

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