(3x) + (x+2) = 102
4x = 100
x = 25
Thus they are 25,26,27
2007-01-07 12:14:50
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answer #1
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answered by daedgewood 4
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Let x = first integer, x+1 = second integer, etc...
3x + (x+2) = 102
4x+2 = 102
4x=100
x=25
The first integer is 25, the next is 26, and the next is 27. =D
2007-01-07 12:16:52
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answer #2
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answered by Lady Irony 2
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n
n + 1
n +2
--------
3n + 3
3(n) + (n + 2) = 102
4n = 102 - 2
4n = 100
n = 25
Answer: The consecutive numbers are: 25, 26 and 27.
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2007-01-07 12:39:27
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answer #3
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answered by aeiou 7
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this is easy just make an equation!
x = first integer
x+1 = second integer
x + 2 = third integer
3x + (x + 2) = 102
you do the rest (all you have to do is solve for x)
2007-01-07 12:16:25
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answer #4
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answered by sur2124 4
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x
x+1
x+2
3(x)+(x+2)=102
4x+2=102
4x=100
x=25
25, 26, 27
2007-01-07 12:15:03
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answer #5
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answered by Joe Blow 1
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