I am having a problem with half.com paying me and every email I have sent them, returns an answer that doesn't help at the least! There has to be a way to speak with someone at their main office.. even if it isn't a free 800 number. Can anyone help me. Thanks!
2007-01-07 11:41:14 · 6 answers · asked by ownedbylabs 2 in Business & Finance ➔ Corporations
ebay is a bunch of crap. my good friend paid 1000 dollars for a tv on ebay and the guy never shipped it to him. Ebay will do nothing about it. they suck
2007-01-07 11:44:02 · answer #1 · answered by miller4000 2 · 1⤊ 1⤋
No Ebay does not have a 1 800 number to call. You can only contact them via email.
2007-01-07 11:49:28 · answer #2 · answered by Mark E 3 · 2⤊ 0⤋
Ebay is the worst besides the shown fact that definitely not the only one. Amazon is close to as undesirable and overstock can't be reached with the aid of employing mobile or digital mail. be careful what you sign for with those adult adult males. a ways greater riskier than apparently. It ordinarily works given which you do not elect a challenge. subjects fixing is rattling close not attainable.
2016-10-30 07:07:35 · answer #3 · answered by ? 4 · 0⤊ 0⤋
ebay is the worst but certainly not the only one. amazon is nearly as bad and overstock cannot be reached by phone or email. be careful what you sign for with these guys. far more riskier than it appears. it usually works so long as you don't have a problem. problems solving is damn near impossible.
2007-01-07 11:44:42 · answer #4 · answered by Anonymous · 1⤊ 0⤋
As all the answers above already tell you if you have a problem with them, you are SOL.
I am in the same situation and am contacting the FTC for false advertising. Thinking about a class action suit too. How about that? Let's sue them!
2007-01-07 12:21:24 · answer #5 · answered by Anonymous · 0⤊ 1⤋
unfortunatly ebay doesn't have a customer support ph # all they offer is email or their live help link, under the "help" tab on their homepage. Good Luck
2007-01-07 11:47:20 · answer #6 · answered by QandA 3 · 2⤊ 0⤋