Stem moves into the cylinder of a steam engine at a constant pressure of 2 times 10 ^5 Pa. The diameter of the piston is 16 cm. and the piston travels 20 cm. in one stroke. How much work is done during one stroke?
2007-01-07 11:06:21 · 4 answers · asked by Kitana 2 in Science & Mathematics ➔ Physics
just multiply them all together, it's force times distance, but i don't have a calculator on me, sorry.
2007-01-07 11:13:39 · answer #1 · answered by way2kewl4u1224 3 · 0⤊ 0⤋
Work = Fd = force (F) applied to moving a distance (d)
F = PA = pressure (P) applied to an area (A); therefore
Work = Fd = PAd; where P = 2 X 10^5 Pa, A = pi r^2 = pi X (16/2)^2 cm^2, r = D/2 = radius of the piston, and d = 20 cm. You can do the math (make sure all your units are consistent).
2007-01-07 11:45:08 · answer #2 · answered by oldprof 7 · 0⤊ 0⤋
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2016-10-30 07:02:01 · answer #3 · answered by gripp 4 · 0⤊ 0⤋
0.16²*π/4 * 2E5 * 0.20 = A*P*S = 804.25 J
2007-01-07 11:20:20 · answer #4 · answered by Steve 7 · 0⤊ 0⤋