ok, I have a problem I have been trying to simplify, I THINK I have the answer, but I am not sure. Could you please simplify this? (and NO this is not my homework, I just want to be able to solve this sort of problem.Thank you
. x^-5w^3/w^2z^-2
2007-01-07 10:59:28 · 12 answers · asked by Anonymous in Entertainment & Music ➔ Polls & Surveys
There should not be a . in front of the x, not like anyone seems to know it anyway =(
2007-01-07 11:02:36 · update #1
FINE, can you email it to a friend who would know how (I am only half serious here)
2007-01-07 11:03:29 · update #2
I got it right YES! woohoo You rock trinity! YAY! (sorry, I am just happy I FINALLY masteredit, I will give you 10 points as soon as possible <(^_^)>
2007-01-07 11:11:25 · update #3
I'll help you on this one...
x^-5w^3/w^2z^-2
= x^-5w/z^-2 (not sure if you're talking about (x^-5)(w^3))
= wz^2/x^5
2007-01-07 11:08:10 · answer #1 · answered by Etania 7 · 0⤊ 0⤋
What i might want to do first, is in each equation, sparkling the fractions by multiply the full equation by the least instantly ahead denominator. x/3 + y/4 = 2 i am going to multiply by 12. 4x + 3y = 24 2x/3 - y/2 = 0 i am going to multiply by 6 4x - 3y = 0 Now you've 2 equations. 4x + 3y = 24 4x - 3y = 0 note that you do not favor to multiply those by anyhting.. the y's cancel out. upload both equations and get: 8x = 24 x = 3 Now change this lower back in: 4x - 3y = 0 4(3) - 3y = 0 12 = 3y 4 = y the answer is (3 , 4). wish that permits!
2016-12-01 23:38:58 · answer #2 · answered by anuj 3 · 0⤊ 0⤋
x^-3w^2/z
You can take away w^2 from both sides, which cancels out the w^2 in the denominator and makes the w^3 be just w. And I think you can square both sides to make the z^-2 just z and the x^-5 be x^-3. But, then the w becomes w^2. I could be wrong, but that's what I would do. =)
2007-01-07 11:08:58 · answer #3 · answered by hgreen_2004 2 · 0⤊ 0⤋
sorry... i wish i knew how to solve that. but maybe my boyfriend can, after all he is better then me in just about EVERYTHING!!
2007-01-07 11:01:27 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Sorry, the best I can do is fractions.
2007-01-07 11:02:04 · answer #5 · answered by Anonymous · 0⤊ 0⤋
yes back in the day. cant do it anymore tho.
2007-01-07 11:02:16 · answer #6 · answered by brock 7 · 0⤊ 0⤋
♥ ♥ nope no math smarts here ♥ ♥
2007-01-07 11:01:24 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Ha ha ha ha! *breathe* hah aha hhahhaaa! *breathe* Hah HAha!
2007-01-07 11:05:22 · answer #8 · answered by ? 5 · 0⤊ 0⤋
LOL, i have no clue how to even start on that one.
2007-01-07 11:01:41 · answer #9 · answered by ? 5 · 0⤊ 0⤋
sorry but i could never figure that one out....ask R2
2007-01-07 11:01:27 · answer #10 · answered by Wicked 7 · 0⤊ 0⤋