I have a triange with 70 degree in the bottom right hand corner I need to solve for x. How do you do that?
2007-01-07 10:46:49 · 5 answers · asked by brighton 3 in Science & Mathematics ➔ Mathematics
well if the bottom right is a 90 degree angle (if theres a box in the bottom right) then you can use sum of the interior angles of a triangle theorm
90+70+x=180
160+x=180
x=180-160
x=20
2007-01-07 10:52:54 · answer #1 · answered by Dill 4 · 0⤊ 0⤋
More information is needed to solve the question. For starters, what does "x" represent? Is it and angle or the length of a side? Is it a right triangle? Where is "x" in relationship to the 70° angle?
If you have an isosceles triangle ABC with AB and AC of equal length, then angles B and C are also equal. If the 70° angle is angle B, then we have:
Angle B = Angle C = 70°
But all triangles have 180°. So
Angle A = 180° - Angle B - Angle C = 180° - 2*70° = 40°
2007-01-07 18:57:43 · answer #2 · answered by Northstar 7 · 1⤊ 0⤋
We need more info. Is this a right triange? Is x a side or the other angle? If this is a right triangle and x is the other angle, then x is 20 degrees. But we need more info
2007-01-07 18:52:13 · answer #3 · answered by gangreless 2 · 0⤊ 0⤋
You didn't give us quite enough info.
Just remember that the angles of a triangle equal 180 degrees. You have 110 left between the other two angles.
If it's a right triangle, that's easy--just subtract another 90 degrees to get 20 degrees for the other acute angle.
2007-01-07 18:50:13 · answer #4 · answered by Iris 4 · 0⤊ 0⤋
To which side does X refer
2007-01-07 18:49:07 · answer #5 · answered by mzuleta2002 2 · 0⤊ 0⤋