GCF... I do it by finding the prime factorization (making a # a product of prime numbers) 70 = 2 × 5 × 7 35 = 5 × 7 what's the largest part that's in both 2 × 5 × 7 and 5 × 7? Well, 5 × 7 or 35 GCF (70 & 35) = 35 LCM Again with prime factorization 10 = 2 × 5 8 = 2 × 2 × 2 the 2 in both equations cancels 1 "2×" out so so LCM (10 & 8) = 5 × 2 × 2 × 2= 40 The first 9 LCMs are the multiples of 40 Namely, 40, 80, 120, 160, 200, 240, 280, 320, 360 QED
2016-05-23 04:59:46
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answer #3
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answered by Anonymous
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1. GCF of 48,64,96
48= 2*2*2 *2*3
64=2*2*2*2*2*2
96= 2*2*2*2*2*3
S0 GCF = 2*2*2*2 = 16
2. GCF of 18,30,60
18 = 2*3*3
30= 2*3*5
60= 2*2*3*5
So GCF = 3
3.GFC of 36,54,135
36= 2*2*3*3
54= 2*3*3*3
135 = 3*3*3*5
GCF = 3*3 = 9
2007-01-07 10:35:15
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answer #4
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answered by ironduke8159 7
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1.) positive divisor of 48 are 1,2,3,4,6,8,12,16,24,48
positive divisor of 64 are 1,2,4,8,16,32,64
positive divisor of 96 are 1,2,3,4,6,8,12,16,24,32,48,96
GCF = 16
2.) positive divisor of 18 are 1,2,3,6,9,18
positive divisor of 30 are 1,2,3,5,6,10,15,30
positive divisor of 60 are 1,2,3,4,5,6,10,12,15,20,30,60
GCF = 6
3.) positive divisor of 36 are 1,2,3,4,6,9,12,18,36
positive divisor of 54 are 1,2,3,6,9,18,27,54
positive divisor of 135 are 1,3,5,9,15,27,45,135
GCF = 9
2007-01-07 10:35:38
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answer #9
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answered by ... 1
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