English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

The width of a rectangle is 40 cm less than its perimeter. The rectangle's area is 102 sq cm

2007-01-07 10:12:29 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

Okay 2w+2l=p, and w=p-40, or 40+w=p.
So, 2w+2l=40+w, or w=40-2l.
And wl=102.
So, (40-2l)l=102.
Or, 2l^2-40l+102=0.
Divide each side by 2, giving you l^2-20l+51=0.
Factoring it, and you get (l-17)(l-3)=0.

So, you can have length=17, and width=6.
And you can have length=3, and width=34.

2007-01-07 10:32:39 · answer #1 · answered by yljacktt 5 · 1 0

I've already answered one of your homework problems, get out your book and figure it out yourself.

2007-01-07 10:21:56 · answer #2 · answered by gangreless 2 · 0 0

fedest.com, questions and answers