Chemistry question?

Question

When 18.465g of element A react completely with 41.25g of element E, compound AE is formed. When 1.19g of A react with 23.94g of element G, compound AG2 is formed. If elements E and G react to form E2G, what mass in grams of G is required to react with 23.99g of element E.

Please show all work

Answer 1

This is a question about molar masses. First, consider AE. 18.465 g of element A contains the same number of atoms as 41.25 g of element E. So element E has a molar mass equal to 41.25/18.465 times that of A. Now consider AG2. 1.19 g of element A contains half as many atoms as 23.94 g of element G, so element G has a molar mass equal to 23.94/(2*1.19) times that of A.

Now you need to consider E2G. An unknown mass, x, of element G must contain half as many atoms as 23.99 g of element E. So element E has a molar mass equal to 23.99/2x times that of G. But we already have information about the molar masses of E and G relative to A. If we let A, E, and G stand in as variables for the molar masses of those elements, we can say that E = A*41.25/18.465 and G = A*23.94/(2*1.19) from the first paragraph, and now we're saying that E = G*23.99/2x. If you substitute in the values for E and G in terms of A, A will cancel out from both sides and you can solve for x.

Answer 2

Better do ALL of your own homework. I am a chem major, you'll never become one if you don't learn it yourself.

good luck.