how many grams are there in3.3 X 10exponent 23 molecules of N2I6?

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how many grams are there in3.3 X 10exponent 23 molecules of N2I6?

2007-01-07 08:52:00 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

2 answers

1) Calculate the molar mass of N2I6
2 x 14.01 + 6 x 126.90 = 789.42 gram

2) Calculate the number of moles
3.3 x 10^23 / 6.022 x 10^23 = 0.548 moles

3) Calculate the mass in grams
0.548 moles x 789.42 gram / mole = 432.6 grams
430 grams with two significant digits

2007-01-07 23:53:43 · answer #1 · answered by cordefr 7 · 0⤊ 0⤋

isn't that just the moler mass. Find the numbers under N and I on the periodic table(N: 14.01, I: 126.9) Times 14.01 by two since you have two nitrogens and 126.9 by 6 since there are 6 Irons, and add the results.

2007-01-07 08:56:02 · answer #2 · answered by moonman 6 · 0⤊ 0⤋