1 4 7 10 13 16 .......
This sequence continues in the same way,' no matter how far you go there will never be a multiple of 3 in the sequence'
am i correct?
2007-01-07 08:37:28 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
this seems too obvious so ill say no, its a trick.
2007-01-07 08:41:56 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The formula for this is 1 + 3(n-1). Now, 3 won't divide into this formula without leaving a remainder of 1, so it will never be a multiple of 3.
2007-01-07 08:42:48 · answer #2 · answered by Scythian1950 7 · 1⤊ 0⤋
the nth term = 3n - 1
If we factor out 3 we get nth term = 3(n - 1/3)
Since n is a whole number n - 1/3 cannot be therefore we will never get a multiple of 3.
2007-01-08 01:53:41 · answer #3 · answered by Mark W 2 · 0⤊ 0⤋
Yep, ur right. The formula can also be written as 3n-2.
2007-01-07 08:50:54 · answer #4 · answered by Anonymous · 0⤊ 0⤋
yes
2007-01-07 08:41:13 · answer #5 · answered by Anonymous · 0⤊ 0⤋