my physics teacher asked this. we were learning about acceleration, and she said tere was something mroe to 9.7, a hint she said: Hint: it is not just acceleration
2007-01-07 07:12:41 · 4 answers · asked by bulbasaur 3 in Science & Mathematics ➔ Physics
thank you for those who answered.btw, we were doing an experiment by dropping a free fall object, then tracked its acaceleration, 9.7...
2007-01-07 07:31:59 · update #1
Odd...the acceleration due to gravity on earth is 9.8 m/sec^2, not 9.7.
2007-01-07 07:16:38 · answer #1 · answered by Jerry P 6 · 0⤊ 0⤋
Gravity, Perhaps. It's the attractive force or acceleration that earth exerts on any object. The gravitational field is numerically equal to the acceleration of objects under its influence, and its value at the Earth's surface, denoted g, is approximately 9.8 m/s². This means that, ignoring air resistance, an object falling freely near the earth's surface increases in speed by 9.807 m/s (around 32 ft/s or 22 mph) for each second of its descent. Thus, an object starting from rest will attain a speed of 9.807 m/s (32.17 ft/s) after one second, 19.614 m/s (64.34 ft/s) after two seconds, and so on.
2007-01-07 15:27:31 · answer #2 · answered by r_dardon 2 · 0⤊ 0⤋
Maybe shes getting at air resitance. Air Resitance will provide an upward accelaration, reducing 9.8 to a lower value. But be careful with this because air resistance affects all things differently (pound of feathers, pound of lead for example)
edit to your add-on: If you measure 9.7 then you could use it to quantify the air resistance
2007-01-07 15:39:33 · answer #3 · answered by evan 2 · 0⤊ 0⤋
The approximate acceleration due to gravity?
2007-01-07 15:15:13 · answer #4 · answered by Anonymous · 0⤊ 0⤋