2 coins & 1 die are simultaneously tossed on a table. What is the probiblity of obtaining 2 heads and a 6?

Answer 1

To answer this question look at the probability of obtaining each possibility:

Probability Dice one comes up head:
There are two choices heads or tails. There is an equal chance it will be heads and an equal chance it will be tails. So the probability it will be heads is one out of two or:
1/2

Coin two coming up heads is same probability of 1/2.

As for the die coming up a 6:
There are 6 different numbers you can roll: A 1, 2, 3, 4, 5, or 6. You have an equal chance any one of these numbers will be rolled. You have 1 chance out of 6 the die will roll a 6. Therefore the probability of rolling a 6 is:
1/6

Final solution:
Probability coin 1 is heads : 1/2
Probability coin 2 is heads : 1/2
Probability die rolls a 6 : 1/6

If you multiply these probabilities you will find the probability of obtaining 2 heads and a 6:
1/2 * 1/2 * 1/6 = 1/24

Answer: The probability of obtaining 2 heads and a 6 is 1/24

Answer 2

Probability of getting 2 heads = 1/2 * 1/2 = 1/4

Probability of getting 6 = 1/6

Probability of getting both = 1/4 * 1/6 = 1 / 24

Answer 3

The probability of a coin being heads is 1/2
The probability of a 6 on a standard die is 1/6
so, if you multiply the three together, you get the probability of two heads and a six:
1/2 * 1/2 * 1/6 = 1/24 or .04166666... or approximately 4.2%

Answer 4

2 x 2 x 6 = 24
Odds are 1 in 24

Sides of Coin x Sides of Coin x Sides of Dice

Answer 5

The probability of obtaining the first head is .5

The probability of obtaining the second head is .5

The probability of obtaining a 6 is .167

So the total probability is .5 * .5 * .167 = .0417

Answer 6

1/2 * 1/2 * 1/6 = 1/24
and = multiply
or = add