Write the equation of the line with slope –2 and y-intercept (0, 0). Then graph the line.?

Question

y = x – 2
y = –2x
y = –2x
y = x – 2
What would this graph look like ?

Answer 1

The equation of a line is in the form y = mx + b.
m = slope
b = y-intersept.

Since the y intercept is at (0,0), the line will cross 0 on the y axis. This means b = 0.

Since m is the slope and the slope = -2, m = -2

Equation of line :
y = -2x + 0
Since anything plus 0 is that anything, -2x + 0 = -2x:

Therefore, the line is:
y = -2x

Ok as for the appearence, since b = 0, which is the y-intercept the line will cross at y=0 (at the orgin)

Since the slope is -2 and that slop is negative the line will decend downwards.

Answer 2

y = mx + b

In this case, m = -2 and b = 0
Plugging
y = -2x + 0
y = -2x

It is a straight line passing through origin (0, 0) and quadrants second and fourth

Answer 3

y = -2x would have a slope of -2 and an intercept of (0,0)
It would be a line sloping downhill from left to right.

Graph (-1,2) (0,0) (1,-2) for an example of what it would look like.

Answer 4

m=-2
b=0
y=-2x

I can't graph it here. it goes through the orgin & contains the points (1, -2); (2, -4) etc.

Answer 5

y=-2x

the graph would be downsloping, pass through the origin (0,0) and be steeper than if it were y=-x

Answer 6

y=mx+b
m= -2
b=0

y= -2x

Answer 7

y = -2x

The graph would look like this:

http://i31.photobucket.com/albums/c392/teekshi33/grapha.jpg

Answer 8

y=-2x