- SQRT 363 X^6 Y^3
Thanks! :)
2007-01-07 05:58:15 · 5 answers · asked by Brad C 1 in Science & Mathematics ➔ Mathematics
Assuming that the X^6 is inside the Sqrt then you can remove it from the Sqrt and change it to X^3.
2007-01-07 06:01:33 · answer #1 · answered by rscanner 6 · 0⤊ 0⤋
SQRT 363 X^6 Y^3 = 11X^3Y√3Y
2007-01-07 06:08:45 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
- √ [363 X^6 Y^3] (noting that √A = A^(½) and so collecting even powers to halve)
= - √ [3 * 121 * X^(2*3) * Y^2*Y]
= - {√ [11² * (X³)² * Y²] * √ [3 *Y] }
= - 11X³Y * √ [3Y]
2007-01-07 06:11:43 · answer #3 · answered by Wal C 6 · 0⤊ 0⤋
363 = 3 x 121 = 3 x (11)^2, so we can extract the square root of 121 from the expression.
x^6 = (x^3)^2, so we can also extract its square root.
y^3 = (y^3/2)^2.
Extracting all of these square roots leaves us with:
11(sq rt 3)[(x^3)(y^3/2)]
2007-01-07 06:12:13 · answer #4 · answered by MathBioMajor 7 · 0⤊ 0⤋
x^3 y^3/2 11 radical 3
2007-01-07 06:09:48 · answer #5 · answered by OSO 3 · 0⤊ 0⤋