I have a problem which I cannot solve and wondered if anyone could help please?
Question:
The damage to road surfaces was proportional to the 4th power of the load. The load of a 44-ton lorry is about 15 times that of a car.
Calculate the ratio of the damage to road surfaces made by a 44-ton lorry and a car.
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(I am aware that, when A is directly proportional to B we have A=kB where k is the constant of proportionality, which in our case would be A=kB^4).
Thank you for your suggestions. :)
2007-01-07 05:13:05 · 4 answers · asked by C H 1 in Science & Mathematics ➔ Mathematics
assume "car-damage" = 1
then lorry-damage = 15^4 = 50625
2007-01-07 05:17:50 · answer #1 · answered by atheistforthebirthofjesus 6 · 0⤊ 0⤋
Hello, not a math genius, but i suggest this.
Look at it this way Damage of Lorry and Damage of Car, which is basically your desired ratio (?)
So
Damage Lorry = K * Load of Lorry ^ 4
Damage car = K * Load of car ^ 4
You know the ratio of car load to lorry load, factor that into the equations and you get you ratio.
Hope it helps
2007-01-07 13:22:42 · answer #2 · answered by dwayne dibbley´s cat 2 · 0⤊ 0⤋
Let D = Damage
Dc= k x L^(4) for a car.
Dl= k(15L)^4 for a lorry.
Dl = 50625 x k x L^(4) for a lorry.
i.e. damage by lorry is 50625 times that of car.
2007-01-07 13:58:19 · answer #3 · answered by Como 7 · 0⤊ 0⤋
15x^4:x^4
lorry:car
x=load of car
2007-01-07 13:19:35 · answer #4 · answered by Zidane 3 · 0⤊ 0⤋