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7 answers

Factor out a 7x:
7x(x^2-4)=0
7x(x+2)(x-2)=0
7x=0
x+2=0
x-2=0
x=0 or ±2

2007-01-07 04:51:08 · answer #1 · answered by Anonymous · 5 0

x =0

2007-01-07 04:41:59 · answer #2 · answered by happyday to you 7 · 0 0

7 x 3 - 28 x = 0 is equivalent to 7(3 - 4x) = 0

Divide both sides of the equation by 7. That leaves 3 - 4x = 0.

Now isolate the variable term: -4x = -3.

Divide both sides by -4: x = -3 / -4 = 3 / 4.

So x = 3 / 4.

As a check, substitute 3 / 4 in for x and see whether it makes the equation true.

2007-01-07 04:51:06 · answer #3 · answered by MathBioMajor 7 · 0 0

quite, that did no longer help plenty... 2x^2 - 2x - 3 = 0 subtract 3 from the two aspects: 2x^2 - 2x = 3 (right this is why...) divide with the aid of by applying 2: x^2 - x = 3/2 halve the 2d term (1x) and placed yet another one in in basic terms for exciting: x^2 - x/2 - x/2 = 3/2 take the coefficient of the 2d term (a million/2), sq. it, and upload it to the two aspects: x^2 - x/2 - x/2 + a million/4 = 3/2 + a million/4 factor out uncomplicated words by applying distribution: x(x - a million/2) - a million/2(x - a million/2) = 3/2 + a million/4 returned (additionally combining like words): (x - a million/2) (x - a million/2) = 6/4 + a million/4 simplify: (x - a million/2)^2 = 7/4 sq. root the two aspects (noting that the sq. root of a great determination must be beneficial or unfavourable): x - a million/2 = (+/-)sqrt(7/4) upload a million/2 to the two aspects: x = a million/2 (+/-) sqrt(7/4) simplify: x = a million/2 (+/-) sqrt(7)/2 x = (a million (+/-) sqrt(7))/2 x = (a million + sqrt(7))/2 or (a million - sqrt(7))/2

2016-12-12 06:10:10 · answer #4 · answered by cheng 4 · 0 0

Factor out a 7x, and go from there.

Don't necessarily trust answers other people give you!

2007-01-07 04:42:01 · answer #5 · answered by Anonymous · 0 0

.75

2007-01-07 04:45:12 · answer #6 · answered by Garret Tripp 3 · 0 0

huh??????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????!

2007-01-07 04:44:08 · answer #7 · answered by danielle d 2 · 0 1

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