2007-01-07 04:38:08 · 7 answers · asked by styles4u 4 in Science & Mathematics ➔ Mathematics
x(x-10) + 16 = 0
x^2 - 10x + 16 = 0
x^2-8x -2x+16=0
x(x-8) -2(x-8) = 0
(x-8)(x-2) = 0
which implies that either x=8 or x=2
2007-01-07 04:42:55 · answer #1 · answered by Neelu 2 · 1⤊ 0⤋
x(x -10) + sixteen = 0 x^2 -10x + sixteen = 0 x^2 - 8x - 2x + sixteen = 0 (x - 8)(x - 2) = 0 x = 2, 8 enable L = the size of the rectangle. Then its width, W = L - 5 (length is 5 greater beneficial than width) the area is only A = L*W = 50 L*(L-5) = 50 L^2 - 5L - 50 = 0 L^2 -10L + 5L - 50 = 0 (L -10)(L + 5) = 0 L = 10, -5 because of the fact the size is obviously helpful, then L = 10 feet, and W = L - 5 = 5 feet
2016-10-30 06:15:49 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x(x - 10) + 16 = 0
x^2 - 10x +16 =0
(x-8)(x-2) = 0
x-8 = 0 so x = 8
x-2 = 0 so x = 2
2007-01-07 04:43:37 · answer #3 · answered by ironduke8159 7 · 1⤊ 0⤋
x^2 -10x +16
=(x - 8)(x - 2)
x=8 or x=2
It's been a while! (The ^2 is to the power of 2 or squared)
2007-01-07 04:47:09 · answer #4 · answered by Spoony 2 · 0⤊ 0⤋
distribute the x.......xsquared -10x+16=0
then factor it (x-8)(x-2)=0
set them both equal to 0 ........x-8=0 x-2=0
then solve x=8 or x=2
2007-01-07 04:51:58 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x^2-10x+16=0
(x-2)(x-8)=0
x-2=0
x-8=0
x=2 or 8
2007-01-07 04:42:44 · answer #6 · answered by Anonymous · 1⤊ 0⤋
(x-2)(x+8)
2007-01-07 04:46:27 · answer #7 · answered by naseeruddin s 1 · 0⤊ 0⤋