an observer is 1.5 miles from the launch area of a hot air baloon. soon after lift-off he measures the angle of elevation to the hot air baloon to be 37 degrees . How high is the shuttle at that instant ?
Round to three decimal places
plzz show me work and answer
From a point on a cliff 100 feet above water level an observer can see a ship. the angle of depression to the **** is 10 degrees. how far is the ship from the base of the cliff. tound to three decimal places.
When an airplane leaves the runway, its angle of climb is 18 degress and its speed is 30 FEET PER SECOND and the altitude of the plane after 2 minutes . Round the to three decimal places
plzz give answers and show work
2007-01-07 03:24:47 · 3 answers · asked by dojorno5 2 in Science & Mathematics ➔ Mathematics
1st thing comes first=
p=x (suppose)
b= 1.5 miles
now
since tan37=p/b
tan37=x/7
{now put value of tan37 and simplify it u'll get x}
second now=
here let AB be cliff and CB be distance between ****.
now AB=p=100
and CB=b=x(suppose)
angle of elevation=angle of depression=10 degree
now tan10=p/b
tan10=100/x
{solve for x now putting value of tan10 using calculator}
3rd one last one is sucking my mind
2007-01-07 03:59:45 · answer #1 · answered by Anonymous · 0⤊ 1⤋
No one is going to do your homework missy. I'll tell you what, you make an effort and I'll help you along the way. First, draw a picture. You're dealing with angles and distance, there are many equations out there for that.
2007-01-07 11:27:09 · answer #2 · answered by John R 4 · 1⤊ 1⤋
a) the base distance=1.5miles
angle of elevation=37deg
we want the perpendicular distance:
tanA=p/b
tan37=p/1.5
p=1.13miles
b)we have the base distance=100ft
and the anble to the base=10deg
we need the perpendicular distance
tanA=p/b
tan10=p/100
p=17.6ft
c)the hypotenuse=30x2x60=3600ft
the perpendicular ht:sinA=p/hyp
sin18=p/3600
p=1112.46ft
2007-01-07 11:34:35 · answer #3 · answered by Maths Rocks 4 · 0⤊ 1⤋