write the equation of the line which passes through the point (2,1) & is parallel to the line y=5/2x+6?

Answer 1

If the lines are parallel, that means that the slope is the same. So start with the formula:y=mx+b
Now add the slope:y=5/2x+b
Now plug in the x and y values that were given ((2,1)):1=5/2(2)+b
Solve for b:1=5+b...b=-4
Now put be into the equation:y= 5/2x - 4

Answer 2

A line parallel to y = 5/2x + 6 is
y = 5/2x + k passing through (2, 1)
plugging
1 = 5/2(2) + k
Solving for k = - 4

So the line is
y = 5/2x - 4

Answer 3

U have the Equation of line in slope-intercept form
which is
y=mx+b

compare this by
y=5/2x+6

"m" is called slope
"b"is called intercept of y

m=5/2
b=6
now u have one point of the Required line
so u have to use
this eq

y-y1=m(x-x1)

(x1,y1)=(2,1)
since it is parallel to the given line
hence its slope is equal to the slope of the given line
hence,m=5/2

y-1=5/2(x-2)

2(y-1)=5(x-2)
2y-2=5x-10
hence
5x-2y-10+2=0
5x-2y-8=0
is the Required eq of the line

Answer 4

Simple answer: y=5/2x-4

1) first, let's separate the equation into different parts

y=5/2x+6

y=mx+b.............=y=5/2x+6
m= slope...........=5/2
b= y-intercept....=6

2) what do we know?

~the line is parallel. the slope will be the same; slope=5/2x
~the line lies on (2,1)(x,y).

3) use the equation for a line y1-y2=m(x1-x2) and solve
In this case we know a single point (2,1) so we can say that while x=2, y=1 and we also know the slope, m, so-- 1-y=5/2(2-x).

Simplify-
1-y = 5-5/2x
-y=-5/2x - 4

y=5/2x-4

Now stop using us to do your homework.

Answer 5

we need an equation of a line
given a point and slope.
point=[2,1]
slope=2.5[same as the slope of line given]
y-y1=m[x-x1]
y-1=2.5[x-2]
y=2.5x-4

Answer 6

comparing eqn with y=mx+c, m1= 5/2 now since line are parallel m1=m2
now using one pt formula y-y1=m2(x-x1)
eqn is 5x-2y-8=0

Answer 7

y-1=5/2(x-2)
2y=5x-10+2
2y=5x-8