"The squares of the orbital periods of planets are directly proportional to the cubes of the semi-major .....

Question

"The squares of the orbital periods of planets are directly proportional to the cubes of the semi-major axis of the orbits". what does this mean any help will be appreciated!

thanks

by the way israa a i am 10

Answer 1

It shows the relationship between the planets' distance away from the sun and the amount of time it takes for their year. The farther the planet is from the sun, the longer the year is.

Answer 2

sure. The squares of the orbital era is at as quickly as proportional to the cubes of the semimajor axis. Kepler's 0.33 regulation of Planetary action, which correlates a planet's orbital era with a planet's distance from the solar, could be summed up with the aid of the easy equation: T2 = D3. in this equation, T = the time of the planet's orbital era in Earth years and D = the planet's mean distance from the solar in astronomical instruments (AU). One AU = the mean distance between the Earth and the solar. Kepler's 0.33 regulation governs all bodies orbiting the solar, which is composed of asteroids and comets. it incredibly is as a results of the fact the solar claims greater beneficial than ninety 9.8% of the completed mass of the photograph voltaic equipment. If photograph voltaic equipment bodies have been significantly greater massive, Kepler's 0.33 regulation -- as reported -- would not be sufficient. enable's presume that this physique occurs to have substantial mass -- a million/10th the solar's. Then the equation might desire to be changed M = the mass of the solar and m = the mass of the secondary physique: (M+m) x T2 = D3 once you employ this equation, make helpful you have the orbital era in Earth years, the gap in astronomical instruments and the mass in photograph voltaic lots.

Answer 3

Kepler's 3rd law
This law shows the relationship for the time required for a planet to move around the Sun and the average distance from the Sun. The relationship is that the time squared (t2) is proportional to the distance cubed (d3). Thus, if you knew the time it took to go aournd the Sun and the distance for one planet, you could find values for another.

http://www.school-for-champions.com/science/orbit.htm

Answer 4

This is Kepler's Third Law of Planetary Motion and jt argues that the relationship between its orbit time (a planet's year) and its average distance from its star (its semi-major axis) is the same for all planets.

See figures below for Neptune and Pluto:

Kepler's third law
The squares of the orbital periods of planets are directly proportional to the cubes of the semi-major axis of the orbits.

T^2 is proportional to a^3

T = orbital period of planet
a = semimajor axis of orbit

PLUTO

Semi-major axis: 5,906,376,272 km 39.48 AU
Orbital period: 248.09 years

NEPTUNE

Semi-major axis: 4,498,252,900 km 30.07 AU
Orbital period: 164.88 years

Cubes of: semi-major axes: 27,189.44 (N) and
61,536.3 (P)

Ratio: Pluto to Neptune: 2.263 : 1

Squares of orbital periods: 27,185.41 (N) and 61,548.6 (P)

Ratio: Pluto to Neptune: 2.264 : 1

Slight discrepancy arises from my rounding down the AU figures quoted

Answer 5

The Newton Universal gravitational constant is allways the same ratio of the radius cube of a gravitational mass divided by the mass and divided by the time squared of a mass revolving around it.Now why this happens this way only Eintein's general relativity theory is able to answer that question.

Answer 6

this is according to keplers iii law
T^2 PROPORTIONAL TO R^3

Answer 7

i dont no



im just 9years old