x-3y=4, 2x^-9y^=17?

Question

Please help , I'm new at this subject

Answer 1

Use order of operation

2x- 3 [2x-4y -x + y - 3] + 7 (multiply within the parenthesis)

2x - 3 [x - 3y -3] + 7 (Combine like terms in parenthesis)

ok now you do the rest - just kidding

2x -3x + 9y + 9 + 7 (Multiply the -3 to everything inside the parenthesis)

-x + 9y +16 (Combine like terms)

Answer 2

x - 3y = 4
x = 3y + 4

Second equation, I assumed a quadratic one

2x^2 - 9y^2 = 17
2(3y + 4)^2 - 9y^2 = 17
9y^2 + 48y + 15 = 0
3y^2 + 16y + 5 = 0
3y^2 + 15y + y + 5 = 0
3y(y +5) + 1(y + 5) = 0
(y + 5)(3y + 1) = 0
y = -5 and y = -1/3

x = 3y + 4
y = -5, x = - 11
y = -1/3, x = 3

Answer 3

x-3y=4 equation -1
2x-9y=17 equation-2
multiplying by 2 in first equation and 1 in second equartion
2x-6y=8
2x-9y=17
- + -
subracting x from the above equations
3y= -9
y= -3
subtituting the value of y in equation 1
x-3(-3)=4
x+9=4
x=-5
verification
-5 - 3(-3)=4
-5 +9=4
4=4
(X,Y)={-5,-3}

Answer 4

x-3y=4.....1]
2x-9y=17...2]
double eqn. 1]
2x-6y=8.......3]
2]-3]
we have
-3y=9
y=-3
x=-5
verify
2[-5]-9[-3]=17 ok