z - 2z/3 + z/2 = 5
6(z) - 6(2z/3) + 6(z/2) = 6(5)
6x - 4x + 3z = 30
9z - 4z = 30
5z = 30
5z/5 = 30/5
z = 6
The answer is z = 6
Insert the z answer into the equation
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Check
z - 2x/3 + z / 2 = 5
6 - 2(6)/3 + 6/2 = 5
6 - 12/3 + 3 = 5
6 - 4 + 3 = 5
9 - 4 = 5
5 = 5
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2007-01-07 02:04:18
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answer #1
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answered by SAMUEL D 7
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z - 2z/3 + z/2 = 5
the LCM is 6
6(z) - 6(2z/3) + 6(z/2) = 6(5)
6x - 4x + 3z = 30
9z - 4z = 30
5z = 30
divide both side by 5
5z/5 = 30/5
z = 6
Check :
Put the value of z in equation
z - 2z/3 + z / 2 = 5
6 - 2(6)/3 + 6/2 = 5
6 - 12/3 + 3 = 5
6 - 4 + 3 = 5
9 - 4 = 5
5 = 5
verify the eqaution
2007-01-10 04:38:07
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answer #2
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answered by Kinu Sharma 2
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6
2007-01-07 10:08:43
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answer #3
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answered by Trevadiya P 1
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z is not equal to 5, it's 6.
You need to get a common denominator of 6 on the left hand side. In doing so, you get the result:
6z/6 - 4z/6 + 3z/6 = 5
Combine like terms on the left side, 6 - 4 + 3 = 5, so 5z/6 = 5.
Multiply by 6 on both sides and 5z = 30. Divide by 5 on both sides and z=6. If you sub in to check, you get 6 - 2*6/3 + 6/3, which simplifies to 6 - 4 +3, which equals 5.
2007-01-07 09:49:52
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answer #4
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answered by Brian S 2
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z=6
2007-01-08 22:13:03
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answer #5
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answered by gooberman 1
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Sol.) z-2z/3+z/2=5
=) (6z-4z+3z)/6=5
=) 2z+3z=30
=) 5z=30
=) z=6
2007-01-07 11:42:53
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answer #6
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answered by Anonymous
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6 X Z-2Z/3 + 6 X Z/2=5(TAKING LCM)
2Z-4Z + 3Z=5
5Z-4Z=5
Z=5
VERIFY:-
5z - 4z=5
25 - 20 =5[ by substituting the value of Z as 5}
2007-01-07 10:30:28
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answer #7
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answered by srinu710 4
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z=5.
2007-01-07 09:43:24
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answer #8
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answered by poni_lvr 1
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z=6 how ?
just assign 6 at z will get 5
that solved.
2007-01-10 12:38:18
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answer #9
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answered by fervej 2
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times 6
6z-4z+3z=5*6
5z=30
dividing bt 5
z=6
2007-01-07 09:44:17
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answer #10
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answered by raj 7
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