5 apples are to be given to a grp of 6 boys and 2 girls. Probability of a particular boy D get an apple is..?

Question

I try to do as follows:
Let the event of boy D receive an apple be, A
Hence, n(A) = 6C1 = 6 and,
Sample event, S
n(S) = 8C5 = 56

So, P(A) = n(A)/n(S)
= 3/28
However, the answer given is 5/8.
How come?

But it is given that a particular boy has to somehow receive an apple. How is it possible that the probability is 5/8?

Answer 1

your thinking too hard
the answer is simply 5/8

Answer 2

You're complicating the question ! Be it boys or girls. they still stand a chances to share the apples, so you just divide the 5 apples among all the kids ( 6+2 ). It's just as simple as 5 divided by 8. Hence it is 5/8 .

Answer 3

just think of it like this.......... 5 apples 8 people 5/8 as in 5 apples divided by 8 people.