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2x- 2y=-10 3x=2y=-1, 20x+8y=11 12X-24y=21, 3x+2y=1 2x+10y=1

2007-01-06 21:09:17 · 5 answers · asked by willlovey 1 in Science & Mathematics Mathematics

5 answers

are you seriously asking this?? If you don't know then I'm not telling. That's simple! ask a real question.

2007-01-06 21:12:54 · answer #1 · answered by jpferrierjr 4 · 0 0

Cramers Rule is composed of determinants interior the numerator and denominators. The numerators variety for each variable, yet no longer the denominator. The denominator is | a million a million -a million| | 5 -a million a million| = a million(3 - 2) - a million(-15-a million) -a million(10+a million) increasing for the time of | a million 2 -3| row a million = a million + sixteen - 11 = 6 The numerator for x, which I write as X, is | -a million a million -a million| |-11 -a million a million| in basic terms the previous numbers, yet column one | 0 2 -3| makes use of the constants from the unique difficulty! = -a million(3 - 2) - a million(33-0) -a million(-22+0) increasing for the time of row a million = -a million -33 + 22 = -12 So x = -12/6 = -2. in addition, Y is | a million -a million -a million| | 5 -11 a million| in basic terms the previous numbers, yet column 2 | a million 0 -3| makes use of the constants from the unique difficulty! = a million(33-0)+a million(-15-a million)-a million(0+11) = 33 - sixteen -11 = 6 So y= 6/6 = a million. ultimately, Z is | a million a million -a million| | 5 -a million -11| in basic terms the previous numbers, yet column threee | a million 2 0| makes use of the constants from the unique difficulty! = a million(0+22)-a million(0+11)-a million(10+a million) = 22 - 11 - 11 = 0 So z= 0/6 = 0.

2016-12-12 05:56:49 · answer #2 · answered by ? 4 · 0 0

well class 10 maths I suppose?
I will not SOLVE the equations, but give u the procedure
take matrix X= x and y column wise
take matrix A= 2 and -2 row wise and 3 and -2 column wise
matrix B= -10 and -1 column wise
obtain B1 and B2 matrices [ u must know how i cant show them on keyboard-matrices]
find the determinants of matrices A, B1, B2
determinant is [ad-bc] which shouldnt be=0
the value of x= det B1/ det A
and, value of y= det B2/ det A

hope this helps u :-]

2007-01-06 21:29:27 · answer #3 · answered by Deranged Soul.. 2 · 0 0

For the first question, convert it to a matrix.

[2 -2] [x] = [-10]
[3 2] [y] = [-1]

x = (the determinant of the matrix with the 1st column replaced by -10 and -1 divided by the determinant of the matrix).

y = (the determinant of the matrix with the 2nd column replaced by -10 and -1 divided by the determinant of the matrix).

I'll solve for the determinant of the matrix, and then you go from there. It's equal to 10.

2007-01-06 21:21:26 · answer #4 · answered by Puggy 7 · 0 0

2 unknows and 2 equations... Do the math... Try to illiminate one of the variables thru adding the equations... or set them equal... u can solve that many ways.. But over all.. this is life dude.. hard work makes you all the better... Take it slow and read your chapter,, remember its not the end of the world.. Trying your best every time is all u can do.. And everyone will be proud of you if that was all you did..

2007-01-06 21:22:13 · answer #5 · answered by kirk b 1 · 0 0

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