help w/ j(x)=4 & p(x)=(5x-3)/(x+4)?

Question

For each of the 2 equations above, answer these questions.
a) Is it a function? 1-1?
b) In what interval(s) is it increasing, decreasing?
c) is it bounded above, below, both or neither?
d) does it have an extreme value (ie, high or low points, turning points)?
e) Does it have any roots?
f) Where does it cross the y-axis?
g) Write the relation described

can anyone please help me?

Answer 1

Here is a nice web site:
http://www.ltcconline.net/greenl/courses/154/systfunc/inverse.htm
It states that
"A function y = f(x) is called one to one if for every y value there is only one x value with y = f(x). That is, each y value comes from a unique x value."
So, to answer "a" above, for j(x) = 4, or "y=4", then for every y value is there only one variable x so that y = 4? The answer is clearly no. y is 4 for ALL values of x.
The second function is 1-1 - I tried graphing it using excel, and for eacy y there is only one value of x, although there is a discontinuity at x = -4

b) j(x) is constant, so it does not increase or decrease in any interval. except where it is discontinuous, p(x) is increasing everywhere

c) I'm going to let you do the j(x) ones. they're very easy. Look at the p(x) function to see that it is not bounder above or below.

d) again, look at the p(x) function to see that it does not have an extreme value (unless you count plus and minus infinity)

e) 5x-3 = 0 is a root of p(x), or x = 3/5

f) set x = 0 to determine this for both equations

g) I don't understand this question