what are the solutions for finding the trigonometric point of:
P(-834π) and P(89π/4)
alternative solutions??
please post some links for further reading...
Thank you
(I badly need it)hehe..
2007-01-06 18:05:35 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Philo, π/4 is (1, 1), not what you said.
2007-01-06 18:53:01 · answer #1 · answered by ? 6 · 0⤊ 0⤋
All you have to do is write 89pi as a linear combination of 8 (since the denominator is 4.
89 = 11(8) + 1
Therefore, P(89pi/4) = P( [11(8) + 1]pi/4 ) = P (11(2pi) + pi/4)
= P(pi/4)
For P(-834pi), write 834 as a linear combination of 2.
834 = 2(417) + 0
Therefore, P(834pi) = P(417(2pi) + 0) = P(0)
2007-01-07 02:16:52 · answer #2 · answered by Puggy 7 · 0⤊ 0⤋
After 34 years of math I don't know what you mean by "trigonometric point," and what is your P function? If I had to guess, you're talking about the point on the unit circle that corresponds to the given angle (in radians). If so, then P(-834Ï) = P(0) = (1,0), and P(89Ï/4) = P(22.25Ï) = P(Ï/4) = (surprise, surprise) (0,1). It's all about coterminal angles, nyet?
2007-01-07 02:23:15 · answer #3 · answered by Philo 7 · 0⤊ 0⤋