area of any triangle = ½base * height
But Hero's formula is useful, if you know the sides (a, b and c) but not the height
A = √[s(s - a)(s - b)( s - c)]
where s = ½ (a + b + c) (= semi-perimeter)
For an equilateral triangle A = ½ (bh)
But h = √3 * b/2
So A = √3 b² /4 where b = length of side
Note ... for an equilateral triangle hero's formula is as follows ... a = b = c and s = 3b/2
So s - a = s - b = s - c = 3b/2 - b = b/2
So A = √[s(s - a)(s - b)( s - c)]
= √[3b/2* b/2 * b/2 * b/2]
= √[3b^4 / 16]
= √3 b² /4 (same as above)
2007-01-06 17:28:23
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answer #1
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answered by Wal C 6
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Sure they can. Isosceles, Scalene and Equilateral refer to the relationship between the lengths of the sides in a triangle. Just because the sides are different lengths doesn't mean that they can't share the same area.
2016-05-23 02:04:43
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answer #2
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answered by ? 3
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Area of scalene triangle is √[s(s - a)(s - b)(s - c)]
where s = a+b+c/2
Area of equilateral triangle is √3/4 a^2...
2007-01-06 22:06:16
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answer #3
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answered by Akshitha 5
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by Heron's formula, if a, b, and c are the lengths of the three sides of a triangle, then the semi-perimeter
s = (1/2)(a + b + c), and the area
A = √[s(s - a)(s - b)(s - c)]
An equilateral triangle has an area of (s^2√3)/4, where s = the length of one side.
2007-01-06 17:27:11
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answer #4
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answered by Helmut 7
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Area of a triangle: A = (1/2)b*h, where b denotes the base & h denotes the height, height is the length of a perpendicular line from the vertex, opposite the base, to a point on the base.
2007-01-06 17:10:27
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answer #5
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answered by Anonymous
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(base x height) /2
just remember height isnt the measure of any side except for in a right triange... it is the measure from the vertex that is not connected with the base line to the point where a line would meet perpendicularly with the base
2007-01-06 17:01:51
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answer #6
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answered by began91 2
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