a river 3 m deep and 40 m wide is flowing at the rate of 2 km per hr .how much water will fall into it in 1m?

Answer 1

The cross-sectional area of the river is 3m X 40m. or 120m^2

At 2 km/hr for 1m (assume you mean minute), you will have
2km/60 water flow, or 2000m/60 flow.

Volume is 120m^2*(2000m/60).

120m^2*2000m/60 = flow
4000m^3 = flow in 1m

Answer 2

in 1m?
if it means 1 minute then
volume of water per unit time= area * velocity
= 3*40*2000 (in 1 hr)
=3*40*2000/60 (in 1 min)
= 4000 m^3 in 1 min

Answer 3

velocity of the present = 3 kmph = 0.833 meter/sec go sectional section = intensity x width = 2 x forty 5 = ninety m^2 So, quantity bypass fee = 0.833 x ninety = seventy 4.ninety 9 OR ~seventy 5 m^3 / sec AS, a million M^3 = one thousand LITRE, quantity bypass fee = seventy 5,000 LITRE/SEC In different instruments, seventy 5 m^3/sec 4500 m^3/minute or 2,70,000 m^3/hour

Answer 4

The question doesn't make sense.