A number when multiplied by 4 exceeds itself by 45.find the number.
2007-01-06 14:20:40 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Let the number be x
By the problem,
4x=x+45
=>4x-x=45
=>3x=45
=>x=45/3=1
2007-01-06 15:29:17 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
Let x = the number in question.
4x = the number multiplied by 4.
A number which exceeds itself by 45 is given by x + 45.
x + 45 = 4x
To solve this, we move all x-terms to the left hand side, and everything else to the right hand side.
x - 4x = -45
-3x = -45
Divide both sides by -3, to get
x = 15
2007-01-06 22:23:36 · answer #2 · answered by Puggy 7 · 1⤊ 0⤋
Say x is the No.
4x=45+x
4x-x=45
3x=45
x=45/3
x=15
2007-01-06 22:24:47 · answer #3 · answered by minootoo 7 · 1⤊ 0⤋
Sol.) Let the number be x
According to the problem:
x + 45 = 4x
=) 3x = 45
=) x = 15
2007-01-07 11:49:19 · answer #4 · answered by Anonymous · 0⤊ 0⤋
a number (n) is 45 less than 4 times itself. The way to set up this equation would be to:
45+n=4n
from here you subtract n from both sides so you would be left with:
45=3n
now you divide 3 from both sides leaving you with:
15=n
so 15 is your answer
2007-01-06 22:35:26 · answer #5 · answered by mvallpro961 2 · 0⤊ 0⤋