O is centre of a circle,BO is bisector of angle ABC.Show AB=AC?

Answer 1

you need more information,
otherwise is not true, just make a picture where AB is small,
AC is big and BO is the bisector....

if you assume that A and C lie on the circle,
then: BO = AO = CO, so consider the following triangles:
AOB and COB, these are congruent, since AO = CO, OB=OB and
the angles ABO and OBC are congruent (by hypothesis)
Therefore AB = BC.

Once again, whiout further hypothesis, I cannot show that AB = AC,
all that I can prove is that the triangle is isosceles, as I did above. .

Answer 2

as attitude TOC is the outdoors attitude of the triangle BOC and BO and CO are bisectors of attitude B and C respectively, we've ?TOC = (a million/2)(?B + ?C). yet as in triangle ABC AB = AC ?B = ?C, so ?TOC = (a million/2)(?B + ?B) = ?B = ?ABC

Answer 3

This is not necessarily true unless you make several assumptions. Please make your question more specific.

For starters, are A, B, and C on the circumference of the circle?