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complete each of the following equations by writing the condensed structural formula for the product that is more likely to form.

a.) CH3CH=CHCH2CH3+H2-->

B.) CH3CH2C(-Cl)HCH2CH3+OH' -->

C.) CH3CH2C=- CCH3+ 2 H2-->

D.) CH3CH2C(-OH)HCH2CH3-- dehydration >

2007-01-06 12:56:57 · 2 answers · asked by babycakez 3 in Science & Mathematics Chemistry

2 answers

a.) CH3CH2CH2CH2CH3

b.) CH3CHCH(OH)CH2CH3

c.) Unintelligible.

d.) CH3CH2CH=CHCH3

2007-01-06 13:11:25 · answer #1 · answered by steve_geo1 7 · 0 0

I'll tentatively agree with Steve. I suspect that (c) is indicating a triple bond, but what occurs depends on the catalyst present. If palladium on carbon (Pd/C) is present, you'll get reduction to the alkane: CH3CH2CH2CH2CH3. However, if Lindlar catalyst is present, you'll get an alkene: CH3CH2CH=CHCH3. The 2 H2 suggests the former. But you have to be aware that mixing hydrogen gas with an alkene or alkyne isn't going to give a reaction in the absence of a catalyst. Which means that (a) needs a catalyst as well (PtO2 and Pd/C are the ones in my textbook).

2007-01-06 13:54:14 · answer #2 · answered by Taco girl 2 · 0 0

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