C = pi D
37.68 = 3.14 x D
D = 37.68 divided by 3.14
D = 12 in
r = 1/2 the Diameter so equals 6 in
Now you know how to do them you can do the remainder
2007-01-06 12:38:13
·
answer #1
·
answered by David C 2
·
0⤊
0⤋
c = pi * 2 radius
radius = c / (2 * pi) equation "1"
area = pi * radius * radius equation "2"
1. radius = 37.68 / (2 * 3.14 ) = 6 using equation "1"
area = 3.14 * 6 * 6 = 113.04 using equation "2"
2007-01-06 17:50:33
·
answer #2
·
answered by Raoof 2
·
0⤊
0⤋
Circumference equals 2*pi*radius.
So you have to rearrange the numbers on each side of the equation until you have the number you don't know on one side.
This would be: Circumference divided by 2 divided by pi equals radius.
2007-01-06 17:41:26
·
answer #3
·
answered by romulusnr 5
·
0⤊
0⤋
I seriously cannot believe that the people on here are doing your work for you. You should really be embarassed about this one. They teach these things in 8th and 9th grade they go over it again. Stop flirting with all the "sexy boys" and grow up and pay attention. Because you wouldn't know if somebody gave you the wrong answer or not if someone wanted to mess you up. Do it for yourself.
Sorry. It will really help you in the long run if you do though.
2007-01-06 17:55:16
·
answer #4
·
answered by Rob 2
·
0⤊
1⤋
C=2(pi)r
1. 37.68=2 (3.14) R
R=6
2. 43.96= 2 (3.14) r
r=7
69.08= 2 (3.14) r
r=11
2007-01-06 17:48:37
·
answer #5
·
answered by ben L 2
·
0⤊
0⤋
C=2*pi*r
r= C/(2*pi)
1) r= 6in
2)r=7in
3)r=11in
2007-01-06 17:43:54
·
answer #6
·
answered by 7
·
0⤊
0⤋
The circumference of a circle is C = 2r(pi), so the radius is r = C / 2(pi)
2007-01-06 17:40:13
·
answer #7
·
answered by JasonM 7
·
0⤊
0⤋
C=2(pi)r
so,r=C/2(pi)
implying in the values will give u
1.r=6 in.
2.r=7 m.
3.r=11 cm.
Area=(pi)(r)(r)=(pi)r^2
2007-01-06 17:43:14
·
answer #8
·
answered by Anonymous
·
0⤊
0⤋
C=2pi*r
So divide by 2i
37.68/6.28 = 6"
43.96/6.28 = 7m
69.08/6.28 = 11cm
2007-01-06 17:40:56
·
answer #9
·
answered by Steve A 7
·
0⤊
0⤋
I agree with Modulo_function
2007-01-06 18:09:14
·
answer #10
·
answered by dagable 2
·
0⤊
1⤋