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Question

Hi all. i am having my math o level test tomorrow so can u help me solving this question?
thanx
the question is:
solve this :

2
______
x-3
_

1
______
x+4
P.S: i mean as fractions.

Answer 1

2/(x-3) - 1/(x+4) =
common denominator is (x-3)(x+4)
(2(x+4) - 1(x-3)) / (x-3)(x+4) =
(2x + 8 - x + 3) / (x-3)(x+4) =
(x+11)/(x-3)(x+4)

Answer 2

I assume that you mean:

2/(x-3) - 1/(x+4) , right?

You 'solve' when there's an equation. This is just an expression. Do you want to simplify it?

To combine fractions they must have the same denominator. So, your first step is to find a common denominator.
The product: (x-3)*(x-4) is the common denominator.

The easiest thing to do is multiply the first fraction by (x+4)/(x+4)
and the second by (x-3)/(x-3)

This will give both terms the same denominator and so they can be added.

Answer 3

*Determine the LCD (least common denominator) > in this combine the denominators > (x-3)(x+4)

First: multiply the fractions by the missing term (top and bottom) to get the LCD for both fractions >

(x+4)(2)/(x+4)(x-3) - (x-3)(1)/(x-3)(x+4)

Sec: combine the numerators and place them over the LCD >

[(x+4)(2) - (x-3)(1)]/(x-3)(x+4)

[2x + 8 - x + 3]/(x-3)(x+4)

[2x - x + 8 + 3]/(x-3)(x+4)

[x + 11]/(x-3)(x+4)

Answer 4

2/(x-3) - 1/(x+4)
You have to get a common denominator by multiplying the denominators (x-3)(x+4)

2(x+4) / (x-3)(x+4) - 1(x-3) / (x-3)(x+4)
(2x + 8) / (x-3)(x+4) - (x - 3) / (x-3)(x+4)

Combine the numerators. 2x + 8 - x + 3 = 14

Answer: (x + 11) / (x-3)(x+4) or (x + 11) / (x^2 + x - 12)

Answer 5

i think the answer is x +11 / x^2 + x - 1