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1. Find the hypotenuse of a right triangle if the legs are 6 and 8.

2.A man borrowed $5,000 and agreed to pay 11and a half% simple interest. If he repaid the loan in 6 months, how much interest would he pay?

3.At an annual rate of$0.40 per$100, what is the annual fire insurance premium for a house that is insured fo $80,000?

4.If school tax rate in a community is $33.50 per $1,000 of assesed valuation, find the amount of tax on property assessed at $50,000.

5. A store sold suita for $65 each. the suits costt the store $50 each. The percentage of increase of selling price overcost is?

6.What is the simple interest on $465 for 2 years at 2 and a half%?

7. 27/64 expressed as a percent is?

8. If a steel bar is 0.39 feet long, what is its length in inches?

2007-01-06 08:03:00 · 5 answers · asked by rbd fan 1 in Science & Mathematics Mathematics

5 answers

1. 10.
2. It depends how often the interest is compounded, really, but I'd guess they want 5000 x .115/2 = $287.50.
3. 80k (.4/100) = $320.
4. 50k (33.5/1k) = $1675
5. 65/50 = 1.3, so they make a 30% profit.
6. 465 (1.025)^2 = $488.54
7. 27/64 = 0.421875 = 42.1875%
8. .39 ft (12in/ft) = 4.68 in

2007-01-06 08:50:46 · answer #1 · answered by Jim Burnell 6 · 0 0

1. Find the hypotenuse of a right triangle if the legs are 6 and 8.

Let hypotenuse be a and the legs be b and c

Then by Pythaogoras' rule

a² = b² + c²
= 6² + 8²
= 100
So a = √100
= 10

2.A man borrowed $5,000 and agreed to pay 11and a half% simple interest. If he repaid the loan in 6 months, how much interest would he pay?

I = Prt/100
= $5000 * 11.5/100 * 1/2 (6 months = 1/2 year)

= $5000 *23/400
= $287.50

ie Interest paid = $287.50

3.At an annual rate of $0.40 per $100, what is the annual fire insurance premium for a house that is insured for $80,000?

Premium = $0.40 * $80,000/$100
= $320

4.If school tax rate in a community is $33.50 per $1,000 of assesed valuation, find the amount of tax on property assessed at $50,000.

School tax = $33.50 * $50,000/$1000
= $1675

5. A store sold suits for $65 each. The suits cost the store $50 each. The percentage of increase of selling price over cost is?

Percent increase of selling price over cost = $15/$50 * 100%
= 30%

6.What is the simple interest on $465 for 2 years at 2 and a half%?

I = Prt/100
= $465 * 2.5/100 * 2
= $23.25

7. 27/64 expressed as a percent is?

27/64 = 27/64 * 100%
= 42.1875%

8. If a steel bar is 0.39 feet long, what is its length in inches?

0.39 ft = 0.39 * 12 in
= 4.68 in.
__________________________ __________________________

Jim the interest in Q's 2 and 6 was given as SIMPLE Interest not compound. So I = PRT/100 NOT A = P(1 + r/100)^n

2007-01-06 16:49:50 · answer #2 · answered by Wal C 6 · 0 0

1. this can be done easily with the Pythagorean Theorem, a^2+b^2=c^2, where a and b are the lengths of the legs, and c is the length of the hypotenuse.

2. simple interest basically means that interest is only ever compiled off of the starting amount. So, you would have to find the interest by multiplying 5000 by .115 and then multiplying that answer by six (for six months).

3. since 100 is 1/800th of 80,000, .40 will be 1/800th of whatever the insurance premium is. You can now just multiply out.

4. see #3

5 To find % increase you find the final price-the initial price divided by the initial price time 100. So, in this case, {(65-50)/50}*100

6. See #2

7. to find a percent, you divide out the fraction, then multiply by 100

8. here you need to convert feet to inches. you can do this by multiplying by 12 as there are 12 inches in one foot.

2007-01-06 16:59:27 · answer #3 · answered by wepter1 1 · 0 0

For 1: use the Phytagorean Thearom
a(b)+b(b)=c(c)
6(6)+8(8)=C(C)
so..: 36+64=c(C)
so..: 100=C(C) this is da same as the square root of 100 which is...

For 7: get a calculator and do 27/64 yull get: 0.421875 = 42%

For 8: do .39*12

2007-01-07 00:08:44 · answer #4 · answered by dudecool718 1 · 0 0

these are all easy questions but it looks like you want someone to do your homework for you

2007-01-06 20:09:50 · answer #5 · answered by David C 2 · 0 0

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