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100g of Minty Marvels cost $2.40 and the pricier Orange Ovals cost twice as ,uch. When 2 Orange Ocals weigh as much a 5 Minty Marvels which themselves weigh in at 10g each, how many Orange Ovals would yo get for $3.60?

If you can help me with this I will give you ten points

2007-01-06 05:54:40 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

Let x = weight of Orange Oval and M = weight of Minty Marvel

Then 2 x = 5 M --> x = 5/2 M

So x = 5/2 (10 g) = 25 g.

Let C(O) = Cost of Orange Oval / 100 g and C(M) = Cost of Minty Marvel / 100 g.

Then C(O) = 2 C(M) = 2 ($2.40 / 100) = $4.80 / 100 g = $0.048 / g.

Number of grams, G,we can buy with $3.60 is:

G = ($3.60) / ($0.048 / g) = 75 g.

Let N(O) be the number of Orange Ovals we can buy.

Then N(O) = 75 g / x = 75 g / 25 g = 3.

We can buy 3 Orange Ovals with $3.60.

2007-01-06 08:12:39 · answer #1 · answered by MathBioMajor 7 · 0 0

5 Minty Marvels weigh 50 g, so 2 Orange Ovals weigh 50 g. Therefore 10 Minty Marvels weigh 100 g, so you can get 10 Minty Marvels for $2.40. Then you can get 1 Minty Marvel for $0.24. So you can get 1 Orange Oval for $0.48. If you divide, then you will get that you can buy 7.5 Orange Ovals for $3.60.

I hope that helps and that it's right.

2007-01-06 14:07:02 · answer #2 · answered by me 2 · 0 0

You would get 3 Orange Ovals.

2007-01-06 14:06:58 · answer #3 · answered by Rosefae 2 · 0 0

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