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Ok I am crocheting an afghan using three different sized motifs. I suck at math. One motif is 14 sq inches, one is 12 sq inches and one is 7 sq inches. I want the finished product to have the following for each row : one 12 one 14 one 7 and then repeat once. How many of each do I make to have the bottom row come out even.?

2007-01-06 04:34:27 · 2 answers · asked by cookyaustinchic 3 in Games & Recreation Hobbies & Crafts

2 answers

Try this and you will have an afghan measuring 84" long x 60" wide.

There will be 5 vertical rows.

Row 1: create six 14" blocks
Row 2: create seven 12" blocks
Row 3: create twelve 7" blocks
Row 4: create seven 12" blocks
Row 5: create six 14" blocks

Sew each of the vertical row blocks into the 5 rows. Then sew the 5 rows together in the designated order. (By sewing I mean whip stitching the blocks together).

This will give you a nice size afghan. Good luck with the project.

2007-01-07 07:07:03 · answer #1 · answered by kitten 3 · 0 0

If by *even* you mean that you want the pattern to be balanced, first you need to determine what width you want your final afghan to be. By placing your 14 inch motif in the center, and bracketing it with a 12 inch and 7 inch motif on either side you would end up with a 52 inch wide afghan . You could do this in columns of each size with borders around both the 12 inch and 7 inch motifs to make up 14 inches so that they would be all the same size motifs for assembly.

2007-01-06 12:40:30 · answer #2 · answered by mickiinpodunk 6 · 0 0

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