Solve this problem?

Question

If Leah is 6 years older than her sister, Sue, and John is 5 years older than Leah. And Leah's and John's age both added up together is 41.

Then how old is Sue?

Help me I've trying to solve this problem for 15 minutes! Any way to solve it showing the steps.

Answer 1

Leah is 6 years older than her sister, Sue. (Sue's age, plus 6, is Leah's age.)

L = S + 6

John is 5 years older than Leah. (Leah's age, plus 5, is John's age.)

J = L + 5

Leah's and John's age both added up together is 41

L + J = 41

You can take the value of J from the 2nd equation (L + 5), and substitute it in for J in the 3rd.

L + J = 41
L + (L + 5) = 41
2L + 5 = 41
2L = 36
L = 18

So Leah is 18.

Then substitute that in the first equation for L:

18 = S + 6
12 = S

So Sue is 12.

(And not that they asked, but John is 18 + 5 = 23.)

Answer 2

Sue=Leah+6
John=Leah+5

Leah+John=41
Leah+(Leah+5)=41
2Leah=36
Leah=18

therefore: Sue=12, Leah=18 and John=23

Answer 3

Let L, S and J be the respective ages and let's write down the equations we're given.
L = S + 6
J = L + 5
L + J = 41

Substitute L + 5 in for J in the third equation:
L + (L + 5) = 41
=> 2L + 5 = 41
=> 2L = 36
=> L = 18 (and hence J = 23, but we don't need that).

Now substitute this into the first equation:
L = S + 6
=> 18 = S + 6
=> 12 = S
So Sue is 12.

In words, since John is five years older than Leah, twice Leah's age plus five years adds up to 41, so her age must be half of 36 i.e. 18. Since she is 6 years older than Sue, Sue must be 12.

Answer 4

assuming Leah's age = L, Sue's age = S & John's age = J

put them in equations,
(1)       L = S + 6
(2)        J = L + 5
(3) L + J = 41

put (2) in (3),
 L + L + 5 = 41
            2L = 36
              L = 18

put L = 18 into (1),
            18 = S + 6
              S = 12

Hence, Sue is 12 years old.

Answer 5

Leah= Sue +6
John =Leah +5
41=Leah +John
(41-5)/2 =18
Leah =18
John=18+5 (23)
23+18=41
Leah (18) -6 =12

Answer 6

Sue is 12

S=X
L=X+6
J=(x+6)+5

John plus leah equals 41 so X+6+X+6+5=41
2X+17=41
2X=24
X=12
So since Sue=X, Sue is 12 (leah is 18, John is 23

Answer 7

leah 6 yrs. older than sue and john
that makes leah the oldest
then sue , and john being the youngest.
that means sue and john are 1 yr. apart.
by being one year apart 1/2 the 41 is 20 1/2
makes sue 21 and john 20 thats 41, and thats the differance
in the 1 yr. apart.
so if sue is 21 and leah being 6 yrs. older
makes leah 27
sue 21 and john 20
i think good luck

Answer 8

*The equations: L = S + 6; J = L + 5 and L + J = 41

1. First: Take (L + 5) and replace it with the "J" variable in the 3rd equation >

L + L + 5 = 41
2L + 5 = 41

Sec: subtract 5 from both sides >

2L + 5 - 5 = 41 - 5
2L = 36

Third: solve for "L" (Leah's age) by isolating it on one side > divide everything by 2 >

2L/2 = 36/2
L = 18

2. First: replace 18 with the "L" variable in the 2nd equation >

J = 18 + 5
J = 23

3. First: take 18 and replace it with "L" variable in the 1st equation >>>

18 = S + 6

Sec: subtract 6 from both sides >

18 - 6 = S + 6 - 6
12 = S

Sue is 12 yrs old

Answer 9

x = Sue's age
x + 6 = Leah's age
(x + 6) + 5 = x + (6 + 5) = x + 11 = John's age

(x + 6) + (x + 11) = 41
x + 6 + x + 11 = 41
x + x + 6 + 11 = 41
(x + x) + (6 + 11) = 41
2x + 17 = 41
2x + 17 - 17 = 41 - 17
2x = 24
2x / 2 = 24 / 2
x = 12

Sue is 12 years old.

Answer 10

sue+6=leah
leah+5=john or...sue+6+5=john
leah+john=41 or...
sue+6 + sue +6+5 =41
sue+sue+17=41
2sue=24
sue=12
got it from there?