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prove that actual circumference of a circle is 2(pi)Rsin(r/R) where R is the radius of universe curvature.?

2007-01-05 23:49:34 · 1 answers · asked by ahopai 1 in Science & Mathematics ➔ Astronomy & Space

1 answers

Rsin(r/R) certainly approaches r as R gets bigger without bound. That is a required property of the correct formula.
I hope that helps some but I don't have a proof.

2007-01-08 16:24:05 · answer #1 · answered by anonimous 6 · 0⤊ 0⤋

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