I'm looking for horizontal force, should frictional and applied force be always the same?

Question

...here?:

A child weiging 200 N swings on a rope.
The child is to be held such that the rope is at an angle of 37 degrees with the vertical.
What is the magnitude of the horizontal force acting on the child?

Answer 1

It is not frictional force.

Here it is the tension in the rope that is balancing the child.

Resolving the tension T into two components,

T cos 37 equals the weight of the child and

T sin 37 equals the applied force.

{ sin is opposite / hypotenuse; in this problem opposite to the angle 37 is the horizontal line.
cos is adjacent / hypotenuse; the vertical line is adjacent to this angle.}

T = 200/ cos 37 = 250.42 N

The horizontal force = T sin 37 = 150.7 N.

Answer 2

37 degrees angle forms a tringange of 3:4:5 ratios.

Child is 200N. It is a direct vertical force. We need to balance this force with -200 N,

So ratio of 4 is 200 N

We are asked of the horizontal force whic has a ratio of 3

( 200 / 4 ) * 3

= 150N

150N's of horizontal force will keep the child stable.



And by the way , this solution is just only in simple psyics. There are muuuuch more force on that child.. =) :P

Answer 3

Okay I can answer your first question...

frictional and applied force are not supposed to be the same because if the frictional force is to the applied force, then there will be no movement. In other words, your push will do nothing to the object because the friction of the object will be exactly the same

Answer 4

Frictional force is almost always in the opposite direction of applied force.

Answer 5

working on it now